Maths
21.The approximate diameter of Sun is 4198600000000 Km. Represent it in:-
2. Standard form
b. Exponential form.
22. The approximate length of river is 39687.869 Km. Write it in:-
a. Standard form
b. Exponential form
Answers
Solution:
1)
a)
4198600000000 Km
To right in the standard form we write it as the multiply of 10 to some power
4198600000000 Km = 4.1986 × 10^12 Km
= 4.1986 × 10^12 × 10³ m
= 4.1986 × 10^15 m
b)
To write in the Exponential form
4198600000000 = 4000000000000 + 198600000000
= 4 × 10^12 + 100000000000 + 98600000000
= 4 × 10^12 + 1 × 10^11 + 90000000000 + 8600000000
= 4 × 10^12 + 1 × 10^11 + 9×10^10 + 8600000000
= 4 × 10^12 + 1 × 10^11 + 9×10^10 + 8000000000 + 600000000
= 4 × 10^12 + 1 × 10^11 + 9 × 10^10 + 8 × 10^9 + 6 × 10^8
Thus
4198600000000 Km=4×10^12 + 1×10^11 + 9×10^10 + 8×10^9 + 6×10^8
2)
a)
To right 39687.869 km in the standard form
39687.869 km = 3.9687869 × 10^4 × 10³ m
= 3.9687869 × 10^7 m
Thus
39687.869 km = 3.9687869 × 10^7 m
b)
39687.869 km =3×10^4+9×10^3+6×10^2+8×10^1+7×10^0+8×10^-3+6×10^-2+9×10^-3