Question

Maths
A milkman uses a container, in the shape of frustum of a cone, to store milk. The container open from the top, is of height 40 cm with radii of its lower and upper circular ends as 14 cm and 35 cm respectively. Find the volume of milk (in litres) which can completely fill the container. If he sells the milk at Rs. 35 per litre, for how much amount he can sell the whole milk ?

Answer 1

Height of the frustrum(H)=40cm

smaller radius(r)=14cm

and larger one(R)=35cm

Therefore volume =1/3pieH(r^2+R^2+Rr)

1/3 ×40×pie(196+1225+70+420)

1/3×22/7×40×1911

91×40×22

6380×11

70180cm^3

=70.180 litres

At rate of 35/liter

Total money=70.180×35

2460.3 rupee