Question

Maths answer it by step by step​

Answer 1

Given :

• $\small\bf\:\frac{y-2}{3}=y-\frac{y-1}{2}$

‎

To find :

• The value of y.

‎

Solution :

$\small\bf\:\frac{y-2}{3}=y-\frac{y-1}{2}$

Calculating LCM of 1 and 2 in RHS

• LCM of 1 and 2 = 2

$\sf\dashrightarrow\:\frac{y-2}{3}=\frac{2y-(y-1)}{2}$

$\sf\dashrightarrow\:\frac{y-2}{3}=\frac{2y-y+1)}{2}$

$\sf\dashrightarrow\:\frac{y-2}{3}=\frac{y+1}{2}$

Cross multiplying

$\sf\dashrightarrow\:3(y+1)=2(y-2)$

$\sf\dashrightarrow\:3y+3=2y-4$

$\sf\dashrightarrow\:3y-2y=-4-3$

$\sf\dashrightarrow\:$$\small\red{\bf\pmb{y=-7}}$

_________________________

Verifying :

$\small\bf\:\frac{y-2}{3}=y-\frac{y-1}{2}$

‎$\sf\to\:\frac{-7-2}{3}=-7-(\frac{-7-1}{2})$

‎$\sf\to\:\cancel{\frac{-9}{3}}=-7-(\cancel{\frac{-8}{2}})$

‎$\sf\to\:-3=-7+4$

‎$\sf\to\:-3=-3$

Hence Verified!~

════════════════════════‎

Therefore,

⠀⠀⠀⠀⠀⠀⠀The value of y is -7.‎

‎

Answer 2

Step-by-step explanation:

$Given :</p><p></p><p>\small\bf\:\frac{y-2}{3}=y-\frac{y-1}{2}3y−2=y−2y−1</p><p></p><p>‎</p><p></p><p>To find :</p><p></p><p>The value of y.</p><p></p><p>‎</p><p></p><p>Solution :</p><p></p><p>\small\bf\:\frac{y-2}{3}=y-\frac{y-1}{2}3y−2=y−2y−1</p><p></p><p>Calculating LCM of 1 and 2 in RHS</p><p></p><p>LCM of 1 and 2 = 2</p><p></p><p>\sf\dashrightarrow\:\frac{y-2}{3}=\frac{2y-(y-1)}{2}⇢3y−2=22y−(y−1)</p><p></p><p>\sf\dashrightarrow\:\frac{y-2}{3}=\frac{2y-y+1)}{2}⇢3y−2=22y−y+1)</p><p></p><p>\sf\dashrightarrow\:\frac{y-2}{3}=\frac{y+1}{2}⇢3y−2=2y+1</p><p></p><p>Cross multiplying</p><p></p><p>\sf\dashrightarrow\:3(y+1)=2(y-2)⇢3(y+1)=2(y−2)</p><p></p><p>\sf\dashrightarrow\:3y+3=2y-4⇢3y+3=2y−4</p><p></p><p>\sf\dashrightarrow\:3y-2y=-4-3⇢3y−2y=−4−3</p><p></p><p>\sf\dashrightarrow\:⇢ \small\red{\bf\pmb{y=-7}}y=−7y=−7</p><p></p><p>_________________________</p><p></p><p>Verifying :</p><p></p><p>\small\bf\:\frac{y-2}{3}=y-\frac{y-1}{2}3y−2=y−2y−1</p><p></p><p>‎\sf\to\:\frac{-7-2}{3}=-7-(\frac{-7-1}{2})→3−7−2=−7−(2−7−1)</p><p></p><p>‎\sf\to\:\cancel{\frac{-9}{3}}=-7-(\cancel{\frac{-8}{2}})→3−9=−7−(2−8)</p><p></p><p>‎\sf\to\:-3=-7+4→−3=−7+4</p><p></p><p>‎\sf\to\:-3=-3→−3=−3</p><p></p><p>Hence Verified!~</p><p></p><p>════════════════════════‎</p><p></p><p>Therefore,</p><p></p><p>⠀⠀⠀⠀⠀⠀⠀The value of y is -7.‎</p><p></p><p>‎</p><p></p><p>$