maths ch1 pg 1.36 q23(SM)
Plz. explain in detail step by step
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pranithrahulspr:
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Answered by
6
hey mate
here is the answer...
Answer:
ax⅔+bx⅓+c=0
we know when
a+b+c=0
then
a³+b³+c³=3abc
thus,
(ax⅔)³+(bx⅓)³+c³=3*ax⅔*bx⅓*c
a³x2+b³x+c³=3abc*x^(⅔+⅓)
a³x2+b³x+c³=3abcx¹
a³x2+b³x+c³=3abcx (answer)
(a) is the correct option...
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maths SM ch1 pg1.35 Q3,4,5,6
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maths SM ch1 pg1.35 Q3,4,5,6
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Answered by
3
Answer:
here's your answer
(a+b)^2. = a^2 + b^2 + 2ab
Step-by-step explanation:
hope it helps you
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