Question

maths class 10
plz answer with step by step explanation
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Answer 1

SOLUTION :

Given : Perimeter of two similar triangles are 25 cm, 15 cm and one of its side is 9 cm..

Let the two triangles be ABC & PQR.

Let one of its side is (AB) = 9 cm and the other side of other triangle be PQ.

Since the ratio of corresponding sides of similar triangles is same as the ratio of their perimeters.

∆ABC ∼ ∆PQR.

AB/PQ = BC/QR = AC/PR = 25/15

9/PQ = 25/15

25 PQ = 15 × 9

PQ = (15×9)/25

PQ =(3× 9 )/5

PQ = 27/5

PQ =  5.4 cm

Hence, the corresponding side of other ∆ is 5.4 cm.

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