Two circles of radii 5 cm and 3 cm intersect at two points and the distance between
their centres is 4 cm. Find the length of the common chord.
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Answer:
chord is of 8 cm
Step-by-step explanation:
by Pythagoras
25-9=AP
AP= 4cm
op perpendicular bisector of ap
AB=2AP
AB=2×4
AB=8cm
hope it will help you
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