Question

MATHS - CLASS X

TRIANGLES

Show an Activity to verify Pythagoras Theorem with a suitable figure.

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Answer 1

Nice question.......
I will try my best to explain it to you....

To verify the “Pythagoras Theoram”

Materials required:-

1. A peice of cardboard
2. Two sheets of white paper
3. A pair of scissors
4. One geometry box
5. Glue

The theory:-

Pythagoras Theorem: In a right angled triangle, the square of the hypotenuse is equal to the sum of squares of both the base and the perpendicular (other two sides).

Now comes the procedure:-

Step 1. Paste a sheet of white paper on the cardboard and on that paper, draw a right angled triangle ABC, which is right angled at C.
Now, let the lengths of the sides AB, BC and CA be c, a and b units as shown in the first figure(the first picture).

Step 2. Now make four exact copies of the right angled triangle ABC on the other sheet of paper and also construct a square with each side measuring c units.

Step 3. Cut these four triangles and the square, arid arrange them as shown in the second figure(the second picture).

Observations and calculations:-

We observe that by the combination of the square and four triangles, a new square is formed with each side measuring (a+b) units. After that,

Area of the large square formed=area of the square with side c+4 units(area of the triangle ABC)
That means,

$= > (a + b) {}^{2} = c {}^{2} + 4( \frac{1}{2} \times a \times b)$
{So, area of triangle ABC=1/2(a×b)}

$= > ( {a}^{2} + {b}^{2} + 2ab) = {c}^{2} + 2ab$

$= > {a}^{2} + {b}^{2} = {c}^{2}$
So, the square of the hypotenuse of the right angled triangle ABC is equal to the sum of the squares of the other two sides.

Result:-

Pythagoras Theorem is verified.

I hope it helps you.
I worked very hard to think and write it and explain it to you.

Do not mark me as the brainliest please.

Answer 2

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