maths equations.if u answer 25 points
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(1) Given,
Side of traingle A = 150cm
side of traingle B= 120cm
side of traingle c= 200cm
we find area by heron's formula
√S(s-a) (s-b) (s-c) = S= a+b+c/2= 150+120+200/2= 235cm
√235(235-150) (235-120) (235-200)
√235×85×115×35
√5×5×5×5×47×17×23×7
5 is common so 5×5√128639
25√128639cm²Ans
(2] given,
side of traingle a= 9cm
side of " b= 12cm
" " " c= 15cm
Area = √18(18-9)(18-12)(18-15]
" = √18×9×6×3 = 54cm²Ans
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