Question

maths experts ...... plz solve this
the ans is 2
plz show the methods
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Answer 1

Step-by-step explanation:

It's too difficult to write it in here...msg me I'll give you proper answer

Answer 2

Answer:

2

Step-by-step explanation:

$Given: \int\limits^{log3}_0{}\,\int\limits^{log2}_0{e^{x+y}} \, dy \ dx$

(i)

$\int\limits^{log2}_0{} \, e^{x+y} dy$

$=\int e^{x+y} dy$

$=\int e^x e^y dy$

$=e^x \int e^y dy$

$=e^x e^y$

$= e^{x+y}$

$= e^{x+y} + C$

Now,

$\int\limits^{log2}_0 {e^{x+y}} \,$

$= e^x$

(ii)

$\int\limits^{log3}_0 {e^{x}} \ dx\,$

$= e^{log3} -e^0$

$= 3 - 1$

$= \textbf 2$

Hope it helps!