Math, asked by Anonymous, 5 months ago

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Question :
In the given figure, BOC is a diameter of a circle and AB = AC. Then, ∠ABC = ?

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Answers

Answered by ᏚarcasticᏚoul
10

Answer:

(b) 45°

Since an angle in a semicircle is a right angle, ∠BAC = 90°

∴ ∠ABC + ∠ACB = 90°

Now, AB = AC (Given)

⇒ ∠ABC = ∠ACB = 45°

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Answered by Anonymous
19

Answer:

Given:-

BOC is diameter of circle

AB=AC

Find:- Angle ABC

Solution:-

Draw a altitude AO as shown in attachment

From this you can get two similar triangles

Triangle AOB = Triangle AOC

BAO = AOB = Z

AOC = CAO = Z

Triangle ABC = AOB + AOC

ABC = Z+Z = 2Z

We know that...

Sum of angles in a triangle is 180°

A+B+C=180

Z+2Z+Z = 180°

4Z = 180°

Z= 180/4

Z = 45°

So, Angle ABC = 45°

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