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Question :
In the given figure, BOC is a diameter of a circle and AB = AC. Then, ∠ABC = ?
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Answered by
10
Answer:
(b) 45°
Since an angle in a semicircle is a right angle, ∠BAC = 90°
∴ ∠ABC + ∠ACB = 90°
Now, AB = AC (Given)
⇒ ∠ABC = ∠ACB = 45°
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Answered by
19
Answer:
Given:-
BOC is diameter of circle
AB=AC
Find:- Angle ABC
Solution:-
Draw a altitude AO as shown in attachment
From this you can get two similar triangles
Triangle AOB = Triangle AOC
BAO = AOB = Z
AOC = CAO = Z
Triangle ABC = AOB + AOC
ABC = Z+Z = 2Z
We know that...
Sum of angles in a triangle is 180°
A+B+C=180
Z+2Z+Z = 180°
4Z = 180°
Z= 180/4
Z = 45°
So, Angle ABC = 45°
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