Question

Maths - Quadratic Equations
Solve, Urgent​

Answer 1

Step-by-step explanation:

Hope this helps u Please make me as a brainliest

Answer 2

Answer:

x = √6/3 , √6/3

Note:

★ The possible values of the variable which satisfy an equation are called its roots.

★ A quadratic equation can have atmost two roots .

Solution:

Here,

The given quadratic equation is ;

3x² - 2√6x + 2 = 0

Let's find the roots of the given quadratic equation by factorisation using middle term splitting method .

Working rule :

★ Write the given quadratic equation in standard form ( ie ; descending order of degree of variable )

★ The standard form of a quadratic equation is given by ; ax² + bx + c .

★ Split the middle term in such a way that the product of its parts is equal to the product of first term and last term .

Thus,

=> 3x² - 2√6x + 2 = 0

=> 3x² - √6x - √6x + 2 = 0

=> √3x(√3x - √2) - √2(√3x - √2) = 0

=> (√3x - √2)(√3x - √2) = 0

=> x = √2/√3 , √2/√3

OR

=> x = √6/3 , √6/3

Hence,

Required roots are : x = √6/3 , √6/3

(real and equal roots)