Question

Maths Question - find the angle whose supplement is three times of it's complement

Answer 1

$\textbf{Your answer is --}$

Let, angle be x

So, it's supplementary is 180-x and

complement is 90-x


Since , its supplement is three times of it's complement.


Therefore ,

180 - x = 3(90-x)

=> 180 - x = 270 - 3x

=> 2x = 270-180

=> 2x = 90

=> x = 90/2

=> x = 45


$\textbf{Hence, angle is 45°}$


$\textbf{【 Hope it helps you 】}$

Answer 2

Let the angle =x
It's supplement = 180°-x
It's compliment = 90°-x .
According to the question ,
180°-x=3(90°-x)
180°-x=270°-3x
-x+3x = 270° -180°
2x=90°
x=90°÷2
X=45°

The required angle is 45°.

*BE BRAINLY*