Question

Maths question- q16
Pls answer

Answer 1

answer

$m + 1/m = 6\\so, [m + 1/m ]^2=[6]^2\\we will apply the formula of [a+b]^2=a^2+2ab+b^2\\\\so, m^2 + [2*m*1/m] + [1/m]^2 = 36\\m^2 + 2 + 1/m^2 = 36\\m^2 + 1/m^2 = 36-2=34\\\\now,m^2 + 1/m^2 = 34\\so, [m^2 + 1/m^2 ]^2=[34]^2\\we will apply the formula of [a+b]^2=a^2+2ab+b^2\\\\so, [m^2]^2 + [2*m^2*1/m^2] + [1/m^2]^2 =1156 \\m^4 + 2 + 1/m^4 = 1156\\m^4 + 1/m^4 = 1156-2=1154$

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