Question

maths
solve and answer me ​

Answer 1

Answer:

• First, We have to rationalise the denominator:-
• (√3-1/√3+1)*(√3-1/√3-1)
• Using Identity (a-b)^2/a^2-b^2
• (√3-1)^2/(√3)^2-(1)^2
• 4-2√3/2 = 2-2√3
• NOW AS PER THE GIVEN CONDITION:-
• 2-2√3 = a+b√3
• THEREFORE ,
• a=2 and b=(-2)

Answer 2

Step-by-step explanation:

a) taking lhs

$\frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } \\ = \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1 } \\ = \frac{{ (\sqrt{3} - 1})^{2} }{3 - 1} \\ = \frac{3 - 2 \sqrt{3} + 1 }{2} \\ = \frac{2 - 2 \sqrt{3} }{2} \\ = \frac{2(1 - \sqrt{3}) }{2} \\ = 1 - \sqrt{3} \\ = 1 + ( - \sqrt{3} )$

now comparing with rhs we get

a= 1 and b= -1