Max height reached derivation
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Maximum height attained by a vertically projected body is derived in the following way ,
Derivation :
third equation of motion : v² - u² / 2aS
S = v² - u² / 2a
Since S = H ,
H = v² - u / 2a
when the body attains maximum height , v becomes zero
H = -u² / 2a
When the body is traveling upward , a = -g [ the body is moving against the action of gravity ]
H = -u² / 2a
minus gets cancelled on both sides
H = u² / 2g
Hence , the maximum height attained by a vertically projected body is given as ,
Hmax = u / 2g
hope it helped and please mark as brainliest:)
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