Question

max no of moles present in
a) 10 litre H2 gas (STP)
b) 5 litre N2 gas (STP)
c) 3.2 g O2 gas
d) 0.17 g NH3 gas

Answer 1

1 litre contain 6.023*10^23 no of molicule same applies on gram also
best of luck

Answer 2

⚡HERE IS YOUR ANS--

no. of moles= VOLUME OF GAS AT STP/ 22.4(l)

a) 10 l of H2 gas .
= 10/22.4
= 0.447 moles
b) 5 litre of N2 gas

= 5/22.4
= 0.223 moles
c) 3.2 gram of O2 gas
mole = weight in gram/molecular weight
= 3.2/32 = 0.1 mole

d) 0.17 gram NH3 gas.
moles = 0.17/17
= 0.1 mole

✨HOPE IT HELPS YOU ✨