Question

Maximum allowable shear stress in a section is 100 kg/cm2. if bar is subjected to tensile force of 5000 kg and if the section is square shaped, what will be dimension of sides of the squares

Answer 1

Step-by-step explanation:

Given Given Maximum allowable shear stress in a section is 100 kg/cm^2. if bar is subjected to tensile force of 5000 kg and if the section is square shaped, what will be dimension of sides of the squares

• Now τ max = 100 kg / cm^3
• Tensile force = 5000 kg
• Maximum tensile stress will be = force / area
•                                                     = 5000 / a^2
• So a = side of square
• Now minimum tensile stress is 0
• Therefore τ max = maximum tensile stress – minimum tensile stress / 2
•                   100 = (5000 / a^2) – 0 / 2  
•                    So 200 x a^2 = 5000
•                    Or a^2 = 5000 / 200
•                   Or a^2 = 25
•                   Or a = 5 cm  
• Therefore the side of the square is 5 cm

Reference link will be

https://brainly.in/question/8709773

Answer 2

Answer:

A=5cm hope it helps you