Question

maximum and minimum solve quetion

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

first lets find extremes

for that put dy/dx=0

5x^4-20x^3+15x^2=0

5x^4-15x^3-5x^3+15x^2

5x^3(x-3)-5x^2(x-3)=0

5x^3-5x^2(x-3)=0

x=3,0 and 1

d2y/dx2  = 20x^3-60x^2+30x

for 0 it is isolated point

for 3

540-540+90

90

for 1

-10

apply global maximum and minimum

we get

max=90

min=-10