maximum and minimum solve quetion
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rahul594:
solve question
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Answered by
2
Hey user !!
Here's the answer you are looking for
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Here's the answer you are looking for
Please see the attached file for your answer
★★ HOPE THAT HELPS ☺️ ★★
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Answered by
0
Answer:
Step-by-step explanation:
first lets find extremes
for that put dy/dx=0
5x^4-20x^3+15x^2=0
5x^4-15x^3-5x^3+15x^2
5x^3(x-3)-5x^2(x-3)=0
5x^3-5x^2(x-3)=0
x=3,0 and 1
d2y/dx2 = 20x^3-60x^2+30x
for 0 it is isolated point
for 3
540-540+90
90
for 1
-10
apply global maximum and minimum
we get
max=90
min=-10
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