Question

Maximum height is 4m and horizontal range 12 m. what is the velocity of projection

Answer 1

 

H  = (R tan Ф ) / 4 
4  = (12 tan Ф ) / 4

tan Ф = 4/3        sin 2Ф = 2 tan Ф / (1 + tan² Ф)  = 0.96

R = u² sin 2Ф / g  

u² =  12 * g / 0.96  = 25 g /2 

u = 5 √(g/2)