Question

(x^2+x) (x^2+x-2)= 24 solve it.

Answer 1

Let ( x^2 + x) = a

So,

a(a-2) = 24

=> a^2 - 2a - 24 = 0

=> a^2 - 6a +4a - 24 = 0

=> a(a-6) +4(a-6) = 0

=> (a-6) (a+4) = 0


a = 6 and - 4


Now,

=> x^2 +x = 6

=> x^2 +x - 6 = 0

=> x^2 +3x - 2x - 6 = 0

=> x(x+3) - 2(x+3) = 0

=> (x-2) (x+3) = 0

x = 2 and x = - 3

Answer 2

Hi,

Please see the attached file!

Thanks