Question

maximum no of molecules are present in 5L of N2 gas at STP​

Answer 1

Here's your answer

According to Avogadro's law,

22.4 litres of N2=6.022× 10^23

5 litres of N2=?

Answer=(5×6.022×10^23)/22.4

Therefore,

5 litres of N2 contains 1.344× 10^23 molecules

Hope it helps

Answer 2

Answer:

1.344*10^23

Explanation: