Question

Maximum no.of orbital for which n+l=5 is??

Answer 1

Explanation:

These are the 5s, 4p and 3d orbitals. For the 5s orbital, n = 5 and l =0, therefore (n + l) = 5. An s subshell has only one orbital and as an orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5s orbital would be 2

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