Question

Maximum number of H atoms are present in
1g atom of hydrogen
1.5 mole H,
1 mole NHS
O 0.3 mole C6H1206​

Answer 1

Answer:

$1 \: mole \: = 6.022 \times {10}^{23 }$

1g h = 1mole = no. of h atoms = 6.022×10²³

1.5 mole = 1.5×6.022×10²³ = 9.034 × 10²³

1mole of NHS = 6.022 × 10²³ H-atoms

since no. of atom in C6H12O6 is 12

so no. of mole of H atoms = 12× 0.3 = 3.6 mole

no. of H- atoms = 3.6 × 6.022× 10²³= 2. 167 × 10²⁴