Question

Maximum number of O atom are present in
(1) 2 g molecule of glucose
(2) 2 g molecule of acetone
(3) 2 g molecule of ethanol
(4) 2 g molecule of sucrose
​

Answer 1

sucrose.... option (4)..........

Answer 2

The maximum number of atoms are present in 2 grams of glucose that are $3.97\times 10^{22}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$     .....(1)

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms

For the given options:

• For A: 2 g of glucose

The chemical formula of glucose is $C_6H_{12}O_6$

1 mole of glucose contains 6 moles of carbon atom, 12 moles of hydrogen atom and 6 moles of oxygen atom.

Given mass of glucose = 2 g

Molar mass of glucose = 180 g/mol

Putting values in equation 1, we get:

$\text{Moles of glucose}=\frac{2g}{180g/mol}=0.011mol$

Number of O atoms = $(6\times 0.011\times 6.022\times 10^{23})=3.97\times 10^{22}$

• For B: 2 g of acetone

The chemical formula of acetone is $C_3H_{6}O$

1 mole of acetone contains 3 moles of carbon atom, 6 moles of hydrogen atom and 1 mole of oxygen atom.

Given mass of acetone = 2 g

Molar mass of acetone = 58 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetone}=\frac{2g}{58g/mol}=0.0345mol$

Number of O atoms = $(1\times 0.0345\times 6.022\times 10^{23})=2.077\times 10^{22}$

• For C: 2 g of ethanol

The chemical formula of ethanol is $C_2H_{5}OH$

1 mole of ethanol contains 2 moles of carbon atom, 6 moles of hydrogen atom and 1 mole of oxygen atom.

Given mass of ethanol = 2 g

Molar mass of ethanol = 46 g/mol

Putting values in equation 1, we get:

$\text{Moles of ethanol}=\frac{2g}{46g/mol}=0.0435mol$

Number of O atoms = $(1\times 0.0435\times 6.022\times 10^{23})=2.62\times 10^{22}$

• For D: 2 g of Sucrose

The chemical formula of sucrose is $C_{12}H_{22}O_{11}$

1 mole of ethanol contains 2 moles of carbon atom, 6 moles of hydrogen atom and 1 mole of oxygen atom.

Given mass of sucrose = 2 g

Molar mass of sucrose = 342 g/mol

Putting values in equation 1, we get:

$\text{Moles of sucrose}=\frac{2g}{342g/mol}=0.0058mol$

Number of O atoms = $(11\times 0.0058\times 6.022\times 10^{23})=3.84\times 10^{22}$

Learn more about mole concept:

https://brainly.in/question/11303726

https://brainly.in/question/2900456

#learnwithbrainly