Question

The sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the numbers is:

Answer 1

As we know that the sum of three odd numbers cannot be even i.e. one of the prime is even or 2 let one of the other prime is p1 then the third prime is p1+36 now according to question
2+p1+p1+36=100
2p1=62
p1=31
Hence, the primes are

2,31,67