Question

May u please solve this question or give me some clue to solve this question
the correct answer will definitely be marked as brainliest ​

Answer 1

Step-by-step explanation:

mx - ny = m^2 + n^2.....(a)

x-y = 2n ......(b)

solving (b); we get :

x = 2n+y......(c)

substituting the value of (c) in (a); we get :

m(2n+y) - ny = m^2 +n^2

2mn + my - ny = m^2 + n^2

2mn + y(m- n) = m^2 + n^2

y(m-n) = m^2 +n^2- 2mn

y(m-n) = ( m-n)^2

y = (m-n)^2 / m-n

therefore,

y = m-n.................ANSWER...........

now,

x= 2n+y

= 2n +m -n

= m+n...................ANSWER..........

Answer 2

mx- ny = m^2 + n^2 ....(1)

x- y = 2n

Multiply by m both sides

mx - my = 2mn ....(2)

(1)-(2)

my - ny = m^2 + n^2 - 2mn

y( m- n) = ( m- n)^2

y= m- n. ( as m not equal to n so m- n can't be zero)

x= 2n+y = n + m