Mayan travelled 28 km due north and then 21 km due east. what is the least distance that he could have travelled from his starting point
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Mayan travelled 28 km due North = AB
he travelled 21km due East = BC
therefore to find out the least distance he could have travelled from point A =AC
therefore :---
AC ² = AB²+BC² ( Pythagoras theorem)
= 784 +441 km
=1225 km
AC = √1225
AC =35 km
Ans:-- Mayan could have travelled the least distance of 35 km.
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