Math, asked by DIPTIKANTAMAHALI, 1 year ago

Mayank, Deepak and Pawan, each of them working alone can complete a work in 5, 10 and 15 days respectively. If all
three of them work together to complete a work and earn Rs. 12,000, What will be Deepak's share of the earnings?
A. Rs. 2000
B. Rs. 6000
C. Rs. 4000
D. Rs. 3000​

Answers

Answered by jasss42
11

Answer:

4,000

Step-by-step explanation:

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Answered by slicergiza
4

Answer:

D. Rs. 3000​

Step-by-step explanation:

Given,

In a piece of work,

Time taken by Mayank = 5 days,

Time taken by Deepak = 10 days,

Time taken by Pawan = 15 days,

So, the ratio of the time taken by them = 5 : 10 : 15 = 1 : 2 : 3

Now, we know that,

efficiency\propto \frac{1}{time}

So, the ratio of their efficiency = \frac{1}{1}:\frac{1}{2}:\frac{1}{3}

= 6 : 3 : 2

Also,

efficiency\propto wages

Thus, the ratio of wages of Mayank, Deepak and Pawan is 6 : 3 : 2,

Let, Mayank's earning = 6x, Deepak's earning = 3x and Pawan's earning = 2x

Where, x is any positive real number,

So, the total earning = 6x + 3x + 2x = 11x

According to the question,

11x = 12000

\implies x = \frac{12000}{11}

Hence, Deepak's share of the earnings = \frac{36000}{11} = 3272.72

OPTION D would be correct.

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