Question

ME PHYSICS
$. Three forces 2N, 3N and 4N acting
simultaneously on body of mass 2kg are
in equilibrium. If 3N force is now
removed then acceleration of the body
will be
(a) 1.5 m/s2
(b) 1 m/s2
(c) 2 m/s
(d) 3 m/s2​

Answer 1

Answer:

Mark me brailiest

The answer is 2

Answer 2

Initially, the forces acting on the 2 Kg body = 2N, 3N and 4N

If the 3N force is removed the net force acting on the body = $4N-2N=2N$

The mass  of the body = 2 Kg

The acceleration on the is calculated by using the following formula:

$a = \frac{Force\ External}{mass}$

Force external = 2 N

Acceleration =

$=\frac{2N}{2 Kg} \\=1m/s^{2}$

Thus the acceleration is 1 m/s².

Hence, the correct option is (b) 1 m/s².