Mean of 100 observations was found to be 30. At time of re checking 2observations were taken as 32 and 12 instead of 23 and 11 find correct mean
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let the obs are x1,x2,......x100
mean=x1+x2+......+x100/100
=>3000=x1+x2+....+x100
since two variable are wrong
x1+x2+....+x100=3000+23+11-32-12
=2990
so ,mean=2990/100
=29.90
mean=x1+x2+......+x100/100
=>3000=x1+x2+....+x100
since two variable are wrong
x1+x2+....+x100=3000+23+11-32-12
=2990
so ,mean=2990/100
=29.90
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