Question

measure of adjacent angles of parallelogram are (5 x -7)⁰ and (4 x + 25)⁰ find the value of x​

Answer 1

Answer:

Ist angle =(5x-7)°

2nd angle =(4x+25)°

A/Q

Ist angle +2nd angle =180 [ sum of adjacent angle

is 180°]

(5x-7)°+(4x+25)°=180°

5x-7+4x+25=180°

9x+18=180°

9x=180°-18°

9x = 162°

x=162/9

x=18° ( ans )

Answer 2

$\huge\rm\orange{anSwer:}$

${}$

$\bf{{\underline{Given}}:}$

• Measure of the adjacent angles of a parallelogram are $\sf{(5x-7)°}$ and $\sf{(4x+25°)}$

$\bf{{\underline{To~find}}:}$

• The value of ‛ x ’

$\bf{{\underline{Here,~we~know~that}}:}$

• The sum of two adjacent angles in a parallelogram are $\sf{180°}$

$\bf{{\underline{Solution}}:}$

$\sf \: \: \: \: \: \: (5x - 7) + (4x + 25) = 180 \\ \sf : \longmapsto 5x - 7 + 4x + 25 = 180 \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \longmapsto (5x + 4x) + ( - 7 + 25) = 180 \\ \sf : \longmapsto 9x + 18 = 180 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \longmapsto 9x = 180 - 18\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \longmapsto 9x = 162\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \longmapsto x = \frac{162}{9} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf : \longmapsto x = \orange{ \underline{ \boxed{ \bf 18}}}\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\bf\therefore{{\underline{Required~answer}}:}$

$\: \: \: \: \: \: \: \: \: \: \: \sf x = \orange{ \underline{ \boxed{ \bf 18}}}$