Question

measure of sides of a triangle are in arithmetic progression its perimeter is 30 cm and the difference between the longest and the shortest side is 4 cm then find the measures of the sides​

Answer 1

Step-by-step explanation:

let the length of the sides be ( a-d),(a),(a+d). since, perimeter of triangle = sum of all sides. i.e) a-d+a+a+d=30. i.e) 3a = 30. i.e) a=10. according to 2nd condition. a+d-(a-d)=4. i.e) 2d=4. i.e) d=2. length of 1st side is a-d i.e) 10-2=8cm , 2nd side is a is 10 cm and 3rd is a+d i.e) 10+2=12cm