Measure of two adjacent sides of a rectangle are in the ratio of 11:10. If the perimeter of the rectangle is 84 cm , then find its area.
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Answered by
10
We know that perimeter of rectangle =2(l+b)
84=2(l+b)
42=l+b
L/B=11/10
42=11x+10x
42=21x
X=21
42=11(2)+10(2)
42=22+20
42=42
Length=22
Breadth =20
Area of rectangle=l*b
=22*20
=440
84=2(l+b)
42=l+b
L/B=11/10
42=11x+10x
42=21x
X=21
42=11(2)+10(2)
42=22+20
42=42
Length=22
Breadth =20
Area of rectangle=l*b
=22*20
=440
Answered by
0
let the length be (11x) cm and the breadth be (10x) cm . So the perimeter ={2×(11x+10x)}cm= (2×21x)cm =42x cm . ATQ 42x=84 or x =2 cm .If (11x)cm=(11×2)cm=22cm.(10x)cm =(10×2)cm==20cm area=(22×20)cm^2=440cm^2
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