Question

Measures of a triangle are in Ap it's perimeter is 30 cm difference between the longest and shortest side is 4cm find measures

Answer 1

Step-by-step explanation:

let the three sides of an A.P. be

                   a -d  ,  a ,   a+d

PERIMETER = 30 CM

    a -d  +  a +   a+d  = 30

   3a = 30

  a = 10 cm

difference between the longest and shortest side is 4cm

a + d - ( a - d ) = 4

a + d - a + d = 4

2d = 4

d = 2cm

measures are :

 a -d     =   10 - 2 = 8 cm

,  a         =    10cm

,   a+d    =  10 + 2 = 12 cm