Question

median of 17,18,23,25,29,31,35,35,35,37,38,42​

Answer 1

Answer:

35

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$total \: numbers \: are \: 12(even \: number)$

$so \: formula \: is$

${ \frac{n}{2} }^{th} term \: and \: { \frac{n + 2}{2} }^{th \: term}$

$= { \frac{12}{2} }^{th} \: and \: \: { \frac{12 + 2}{2} }^{th}$

${ \frac{12}{2} }^{th} \: \: and \: \: { \frac{14}{2} }^{th}$

${6}^{th} \: and \: {7}^{th}$

${6}^{th} \: term = 31$

${7}^{th} \: term \: = 35$

$average \: of \: ({6}^{th} and \: {7}^{th} )terms$

$= \frac{31 + 35}{2}$

$= \frac{66}{2}$

$= 33$

$therefore$

$median \: of \: the \: given \: data \: is$

$\boxed{\huge\red{33}}$