meena anut was on a long visit of 54 days from dubai. if she reached on 10 may ,on what date would she be leaving. (include 10 may)
Answers
Answer:
Heya Mate.
Let's think and answer ★
Meena's I want to reach there on 10 May.
Total number of days of visit = 54
If including 10 May,
Total number of days in May = 31
Subtract 9 from 31.
Remaining days of May = 31 - 9 = 22
After spending 21 days of May remaining days = 54 - 22 = 32
Next month of May is June.
Total number of days in June = 30
Remaining days after spending June = 32 - 30 = 2 days.
Next month of June is July.
Therefore, meena's aunt would be leaving on
2nd July.
Answer:
Meena's I want to reach there on 10 May.
Total number of days of visit = 54
If including 10 May,
Total number of days in May = 31
Subtract 9 from 31.
Remaining days of May = 31 - 9 = 22
After spending 21 days of May remaining days = 54 - 22 = 32
Next month of May is June.
Total number of days in June = 30
Remaining days after spending June = 32 - 30 = 2 days.
Next month of June is July.
Therefore, meena's aunt would be leaving on