Question

meena is five times as old as her son. In 8 years time meena will be three times as old as her son. Find their present ages​

Answer 1

Answer:

let the axe of meena be x and the age of his son be y

By question,

x=5y

=>x-5y=0_(1)

In 8 years

meena's age=x+8

son's age=y+8

=>x+8=3(y+8)

=>x+8=3y+24

=>x+8-3y-24=0

=>x-3y-16=0

=>x-3y=16_(2)

Now,

subtracting equation 1 and 2,we get

x-5y=0

-x+3y=-16

-2y=-16

y=-16/-2

y=8

Putting the value of y in equation 1,we get,

x-5y=0

x-5*8=0

x-40=0

x=40

Therefore, meena's age is 40 years and her son's age is 8 years.

THANK YOU

Answer 2

Let Meena’s son’s age be x
So Meena’s current age will be 5x
After 8 years,
Meena’s son’s age will be x+8
Meena’s age will be 3(x+8)
According to question:
5x+8=3(x+8)
5x+8=3x + 24
5x-3x=24-8
2x=16
x=16/2
x=8
Meena’s son’s present age =8
Meena’s present age=5*8= 40