Question

Meena went to a bank to withdraw Rs 6,200.

She asked the cashier to give her Rs 200 and

Rs 500 notes only. Meena got 22 notes in

all. Find the number of Rs 200 notes and the number of Rs 500 notes that she received.​

Answer 1

$\sf\large\underline{Let:}$

$\sf{\implies The\: number\:_{(Rs.500\:notes)}=x}$

$\sf{\implies The\: number\:_{(Rs.200\:notes)}=y}$

$\sf\large\underline{Given:}$

$\sf{\implies Total\: withdrawn\: Amount=Rs.6200}$

$\sf{\implies Total\: number\:of\:notes=22}$

$\sf{\implies Types\:of\:notes=Rs.500\:and\:Rs.200}$

$\sf\large\underline{To\: Find:}$

$\sf{\implies The\: number\:_{(Rs.500\:notes)}=?}$

$\sf{\implies The\: number\:_{(Rs.200\:notes)}=?}$

$\sf\large\underline{Solution:}$

• At first set up equation then calculate those equation. After solving you got the value of x and y where x is the number of notes of Rs.500 and y is the number of notes of Rs.200]

$\tt{\implies The\:sum\:of\: number\:of\:notes=22}$

$\tt{\implies Rs.500\:notes+Rs.200\:notes=22}$

$\tt{\implies x+y=22-------(i)}$

$\tt{\implies Total\:sum\:of\:the\: notes=Rs.6200}$

$\tt{\implies 500x+200y=6200------(ii)}$

• In eq 1st multiplying by 500 then subtract from (ii)

$\tt{\implies 500x+500y=11000}$

$\tt{\implies 500x+200y=6200}$

• By this equations we get, here]

$\tt{\implies 300y=4800\implies y=16}$

• Now putting the value of y=16 in eq (I)

$\tt{\implies x+y=22}$

$\tt{\implies x+16=22}$

$\tt{\implies x=22-16\implies x=6}$

$\sf\large{Hence,}$

$\sf{\implies The\: number\:_{(Rs.500\:notes)}=6}$

$\sf{\implies The\: number\:_{(Rs.200\:notes)}=16}$