Meenakshi sells a pen for ₹54 and loss 1/10 of her outlay .Find(1) the cost price of the pen and (2) the loss percent
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Meenakshi sells a pen for Rs.54 and losses 1/10 of her outlay .Find (i)the cost price of the pen ,and(ii)the loss per cent.
Outlay means the Cost Price
Let the CP be m
It is given that Meenakshi loses 1/10 of her CP or 1/10m, so she has 9/10m with her
9/10m = 54
m = 54/ 9/10
m = 54 x 10/9
m = 6 x 10
Therefore, m = 60
(i) CP of the pen = Rs. 60
------------------------
Given: CP = Rs. 60
SP = Rs. 54
Loss = CP-SP = 60-54 = 6
Loss % = Loss/CP X 100
= 6/60 X 100 = 10
(ii) Loss = 10 %
Hope this helps! :)
Outlay means the Cost Price
Let the CP be m
It is given that Meenakshi loses 1/10 of her CP or 1/10m, so she has 9/10m with her
9/10m = 54
m = 54/ 9/10
m = 54 x 10/9
m = 6 x 10
Therefore, m = 60
(i) CP of the pen = Rs. 60
------------------------
Given: CP = Rs. 60
SP = Rs. 54
Loss = CP-SP = 60-54 = 6
Loss % = Loss/CP X 100
= 6/60 X 100 = 10
(ii) Loss = 10 %
Hope this helps! :)
Answered by
10
Let the cost be x
SP= 54 (given)
Loss=1/10 of outlay
i e 1/10x
First find out the loss%
Loss%=(loss/CP) * 100
= (x/10*1/x)*100
Which is equal to 10%
Now selling price= cp-loss% of CP
54 = x-10%of x
= x-10/100x
= 90/100x
54 = 9/10×
X = 540/9
x =60
Hence cp= 60
Loss %=10
SP= 54 (given)
Loss=1/10 of outlay
i e 1/10x
First find out the loss%
Loss%=(loss/CP) * 100
= (x/10*1/x)*100
Which is equal to 10%
Now selling price= cp-loss% of CP
54 = x-10%of x
= x-10/100x
= 90/100x
54 = 9/10×
X = 540/9
x =60
Hence cp= 60
Loss %=10
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