Math, asked by sonukart6153, 1 year ago

Meenakshi sells a pen for ₹54 and loss 1/10 of her outlay .Find(1) the cost price of the pen and (2) the loss percent

Answers

Answered by mdsameer1
36
Meenakshi sells a pen for Rs.54 and losses 1/10 of her outlay .Find (i)the cost price of the pen ,and(ii)the loss per cent.

Outlay means the Cost Price

Let the CP be m

It is given that Meenakshi loses 1/10 of her CP or 1/10m, so she has 9/10m with her

9/10m = 54

m = 54/  9/10

m = 54 x 10/9

m = 6 x 10

Therefore, m = 60

(i) CP of the pen = Rs. 60

------------------------

Given: CP = Rs. 60

SP = Rs. 54

Loss = CP-SP = 60-54 = 6

Loss % = Loss/CP X 100

 = 6/60 X 100 = 10

(ii) Loss = 10 %

Hope this helps! :)

Answered by Iamaditi
10
Let the cost be x
SP= 54 (given)
Loss=1/10 of outlay
i e 1/10x
First find out the loss%
Loss%=(loss/CP) * 100
= (x/10*1/x)*100
Which is equal to 10%
Now selling price= cp-loss% of CP
54 = x-10%of x
= x-10/100x
= 90/100x
54 = 9/10×
X = 540/9
x =60
Hence cp= 60
Loss %=10
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