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let the digits be x and y.
Fraction will be 10x+y.
As per the question,
10y+x -(10x+y) =27
9(y-x) = 27
y-x = 3.
and, x+y = 7 which is given.
Now, By solving both the equations,
x= 2, y= 5.
Thus, Required no. = 25.
Fraction will be 10x+y.
As per the question,
10y+x -(10x+y) =27
9(y-x) = 27
y-x = 3.
and, x+y = 7 which is given.
Now, By solving both the equations,
x= 2, y= 5.
Thus, Required no. = 25.
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