Math, asked by Anuskaverma, 1 year ago

Meenakshi sells a pen for 54rs and loses 1/10 of her outlay. Find (i) the cost price of the pen, and (ii) the loss per cent.

Answers

Answered by Anonymous
3

Step-by-step explanation:

let cp be x

loss%=((x/10)/x)×100=10%

loss%=10%

.9cp=54

cp=60

Answered by MsPRENCY
24

\huge\underline\green{\tt Solution: }

Let Cost price be ' P '

It is given that Selling price of a pen is Rs 54

Loss = \dfrac {1}{10} × P ( outlay means cost price )

Now,

Loss = \dfrac {P}{10}

Loss = C.P - S.P

\dfrac {P}{10} = P - 54

 P - \dfrac {P}{10} = 54

\dfrac {10P-P}{10} = 54

\dfrac {9P}{10} = 54

➡ 9P = 54 × 10

➡ 9P = 540

➡ P = \dfrac {540}{9}

P = 60

\therefore Cost Price of the pen is Rs 60 ------------------ ( i ) answer

Now,

Loss = \dfrac {P}{10}

Loss = \dfrac {60}{10}

Loss = 6

Loss % = \dfrac {loss}{C.P} × 100

= \dfrac {6}{60} × 100

= 10 % -------- ( ii ) answer

Answer : Cost Price of pen is Rs. 60 and Loss percent is 10%

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