Question

Meenakshi sells a pen for Rs.54 and losses 1/10 of her outlay .Find (i)the cost price of the pen ,and(ii)the loss per cent

Answer 1

Outlay is called C.P

Let C.P = X

S.P = ₹ 54 (given)

Loss=(1/10) × X= X/10

Loss = C.P - S.P

x/10= x - 54

x-x/10= 54

(10x - x )/10= 54

9x /10 = 54

9x = 54 × 10

x = (54×10)/9 = 6× 10= 60

C.P = ₹ 60

Loss = x/10 = 60/10= ₹6

Loss = ₹6

Loss% =( loss/c.p) × 100

Loss% =( 6/60) × 100

Loss% = 10

Hence, the C.P of the pen = ₹60 & Loss% = 10
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Hope this will help you....

Answer 2

Solution :-

Let the Cost price of the pen = Rs. x

Meenakshi loses 1/10 or 10 % of his total outlay, when she sell it for Rs. 54.

So, according to the question.

⇒ x - (x*10)/100 = 54

⇒ x/1 = x/10 = 54

Taking LCM of the denominators and then solving it.

⇒ (10x - x)/ 10 = 54

⇒ 9x = 540

⇒ x = 540/9

⇒ x = 60

So, cost price of the pen is Rs. 60

Loss percent = (Loss*100)/Cost price

(6*100)/60

= 10 %

So, loss percentage is 10 %

Answer.