Math, asked by KritarthGPathak, 3 months ago

Meenu bought two fans for 1200 each. She sold one at
a loss of 5% and the other at a profit of 10%. Find the selling price of each . Also find out the total profit or loss.​

Answers

Answered by smrutipratikshya27
11

Answer:

Given  C.P of first fan = Rs 1200

He sold the fan at a loss of 5%

⇒ Loss on first fan= 5% of 1200

             = 5/100*1200

             = Rs 60  

S.P of fan = C.P - loss

                 = 1200 -60

                 = Rs 1140

C.P of 2nd fan = Rs 1200

He sold at a profit of 10%

profit of second fan= 10% of 1200

          = 10/100*1200

          = Rs 120

S.P of 2nd fan = profit + C.P

                         = 1200+120

                         =   Rs 1320

Total cost price of two fans = 1200 + 1200 = Rs 2400

Total S.P of 2 fans = 1320+1140 = Rs 2460

Since S.P > C.P

He got profit on whole

profit = S.P - C.P

          = 2460 - 2400

          = Rs 60

Profit% = profit/C.P * 100

             = 60/2400 * 100

             = 2.5% profit on whole

Answered by shauryashrivastava21
0

Answer:

Meenu gained a profit of 5%

Step-by-step explanation:

Overall CP of each fan = ` 1200. One is sold at a loss of 5%.

This means if CP is ` 100, SP is ` 95.

Therefore, when CP is ` 1200, then SP = `

95/100 * 1200

× = ` 1140

Also second fan is sold at a profit of 10%.

It means, if CP is ` 100, SP is ` 110.

Therefore, when CP is ` 1200, then SP = `

110/100 * 1200

× = ` 1320

Total CP = ` 1200 + ` 1200 = ` 2400

Total SP = ` 1140 + ` 1320 = ` 2460

Since total SP > total CP, a profit of ` (2460 – 2400) or ` 60 has been made.  

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