Meera stepped out of her house to buy some vegetables. She travelled west 9 km from her house, then took a left turn and travelled 6 km to reach
junction 'A'. There she took a right turn and travelled 10 km, then turned 90° in clock-wise direction and travelled 4 km to reach junction B. At 'B' she
turned left to travel 6 km and took a final right turn to reach the market after 8 more km. What is the shortest distance between junction 'A' and the
market?
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Given:
Meera stepped out of her house to buy some vegetables.
To find:
What is the shortest distance between junction 'A' and the
market?
Solution:
From given, we have,
Meera travelled west 9 km from her house, then took a left turn and travelled 6 km to reach junction 'A'.
There she took a right turn and travelled 10 km, then turned 90° in clock-wise direction and travelled 4 km to reach junction B.
At 'B' she turned left to travel 6 km and took a final right turn to reach the market after 8 more km.
Using Pythagoras theorem, we have,
The shortest distance = √[ (10 - 6)² + (8 + 4)²]
= √(16 + 144)
= √160
= 4√10 km
Therefore, the shortest distance is 4√10 km
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