Question

Meeta is twice as old as arushi. 5 yr ago her age was 3 time arushi. Find their present age...

Answer 1

$\huge \boxed{\pink\star\mathfrak\orange{\large{\underline{\underline{Answer!}}}} }$

Let the present age of arushi be x years

Then present age of meeta=2x

Five years ago,

Age of arushi=( x-5 ) years

and age of meeta = (2x-5) years

Now, According to the question

2x-5= 3(x-5)

⟹2x-5= 3x-15

⟹3x-2x= 15-5

⟹$\boxed{\bold\red{x= 10}}$

Arushi's age= x= 10 years

Meeta's age=2x= 2×10= 20 years