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The sides of a rectangular field are in the ratio 9.7 and its perimeter is 144 metres. Find the sides.
The sides of a rectangular piece of paper are in the ratio 2:3. If the area is 150 sq. cm, find the length
of its sides. (Hint: 52-25)
sides of a triangle are in the ratio 2.3:4 and its perim is 63 cm. What are the lengths of its
Answers
Step-by-step explanation:
Given:
- Sides of a rectangular field are in ratio of 9:7
- Perimeter of rectangle is 144 m.
To Find:
- Measure of sides of rectangle?
Solution: Let x be the common in given ratio. Therefore,
➼ Length = 9x m
➼ Breadth = 7x m
As we know that
★ Perimeter of Rectangle = 2(Length + Breadth) ★
A/q
144 = 2(9x + 7x)
144 = 2(16x)
144 = 32x
144/32 = x
4.5 = x
So, Measure of sides are
• Length = 9x = 9(4.5) = 40.5 m
• Breadth = 7x = 7(4.5) = 31.5 m
____________________
Given:
- Sides of a rectangular piece of paper are in ratio of 2:3.
- Area of paper is 150 cm².
To Find:
- Measure of sides of paper ?
Solution: Let x be the common in given ratio. Then,
➼ Length of paper = 2x
➼ Breadth of paper = 3x
As we know that
★ Ar. of Rectangle = Length • Breadth ★
A/q
- area is 150 cm²
150 = 2x 3x
150 = 6x²
150/6 = x²
25 = x²
√25 = x
√5 5 = x
5 = x
So, Measure of sides of rectangular paper are
• Length = 2x = 2(5) = 10 m
• Breadth = 3x = 3(5) = 15 m
___________________
Given:
- Sides of a triangle are in ratio of 2:3:4.
- Perimeter of triangle is 63 cm.
To Find:
- What is the length of its sides ?
Solution: Let x be the common in given ratio. So,
=> First side = 2x
=> Second side = 3x
=> Third side = 4x
As we know that
★ Perimeter of ∆ = Sum of all sides ★
A/q
- Perimeter is 63 cm
63 = 2x + 3x + 4x
63 = 9x
63/9 = x
7 = x
Hence, It's sides are
• First side = 2x = 2(7) = 14 cm.
• Second side = 3x = 3(7) = 21 cm.
• Third side = 4x = 4(7) = 28 cm.