Question

Meiling is thinking of three numbers. the sum of first two number is 738. the second number is 42 more than the third number. The third number is twice the first number .Find the difference between the first number and the second number

plz solve​

Answer 1

Answer:

Step-by-step explanation:

Let three numbers are x, y, z

So from problem given we can get equations as

x + y+z= 66

x=2y

z=1x/3

now we will make equation 1 with only one variable using equation 2 and 3.

y=1x/2 since x=2y

Now using equations 1, 3 and 5 we will get

x+1x/2+1x/3=66

11x/6=66

x= 66*6/11

x= 36

y=x/2=36/2=18

z=x/3=36/3=12

Hence the numbers are 36, 18 and 12

Hope it's helpful dear mark me as brainliests please and support me I am new hereLet three numbers are x, y, z

So from problem given we can get equations as

x + y+z= 66

x=2y

z=1x/3

now we will make equation 1 with only one variable using equation 2 and 3.

y=1x/2 since x=2y

Now using equations 1, 3 and 5 we will get

x+1x/2+1x/3=66

11x/6=66

x= 66*6/11

x= 36

y=x/2=36/2=18

z=x/3=36/3=12

Hence the numbers are 36, 18 and 12

Hope it's helpful dear mark me as brainliest

please and support me I am new here

Answer 2

Answer:

x + y = 738

y = z + 42

z = 2 x X or z = 2x

x + z + 42 = 738

x + 2x + 42 = 738

3 x = 738 - 42

3 x = 696

X = 696 / 3

x = 232

Y = 738 - x

Y = 738 - 232

Y = 506

Difference = 506 - 232

= 274