Question

Meille
re
Revision
400M
1
10 CN = AM
400CM: 400kdo 400
2. 5000CM
1000 MM
5000 CM ​

Answer 1

Step-by-step explanation:

Solution :

Number of photon incident per second

=PowerE≠rgyofo≠pho→n

P(hc/λ)

Number of electrons emitted per second

=0.1 % of

Pλhc=Pλ1000hc

∴Current=char≥(onpho→e≤ctronspersecond)

=Pλe1000hc

=(1.5×10−3(400×10−9)1.6×10−19(1000)(6.63×10−34)(3×108)

=0.48×10−6A=0.48μA.