Question

Members to be elected. If a voter can vote in 30 different ways, find the number of candidates standing for the election if every voter has to vote for at least one candidate and not more than the number of candidates to be elected​

Answer 1

Given :- Members to be elected. If a voter can vote in 30 different ways, find the number of candidates standing for the election if every voter has to vote for at least one candidate and not more than the number of candidates to be elected ?

Answer :-

Let us assume that, the number of candidates standing for the election are n .

so,

→ n(C)1 + n(C)2 + n(C)3 + ____ n(C)(n - 1) = 32

→ 2^n - 2 = 30

→ 2^n = 30 + 2

→ 2^n = 32

→ 2^n = 2⁵

→ n = 5

therefore, there were 5 candidates standing for the election .

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