Math, asked by shahinakhan7919, 1 year ago

Menstruation chapter easy tips

Answers

Answered by tejas2677
0

it was very easy but practice the construction one day before test

Answered by parashuramnalla
1

Answer:

Step-by-step explanation:

Here  are  Some important formulas which are used in mensuration .

Rectangle :

Area = lb

Perimeter  = 2(l+b)

Square :

Area = a×a

Perimeter = 4a

Parallelogram

Area = l × b

Perimeter = 2 ( l + b )

Triangle :

Area =(1 / 2 ) .b . h   or √ s ( s - a ) ( s - b ) ( s - c)…..... S = ( a + b + c ) / 2

Trapezium :

Area = 1/2h(a+b)

Perimeter = Sum of all sides

Rhombus :

Area = ( d1 × d2 ) / 2

Perimeter = 4a

Kite :

Area  = d1×d2/2

Perimeter  = 2 × Sum on non-adjacent sides

Circle :

Area =  πr^2 or πd^2/4

Circumference = 2πr  or πd

Area of sector of a circle = (θπr^2 )/360

Cube :

Volume: V = l^3

Lateral surface area = 4a^2

Surface Area: S = 6s^2

Cuboid

Volume : lbh

Total surface area = 2 (lb + bh + hl) or 6l2

Length of diagonal =√(l^2+b^2+h^2)

Right Circular Cylinder :

Volume  = π r2 h

Lateral Surface Area (LSA or CSA) = 2π r h

Total Surface Area = TSA = 2 π r (r + h)

Volume of hollow cylinder = π r h(R2 – r2)

Right Circular cone :

Volume = 1/3 π r2h

Curved surface area: CSA=  π r l

Total surface area = TSA = πr(r + l )

Sphere

Volume: V = 4/3 πr3

Surface Area: S = 4πr2

Hemisphere :

Volume = 2/3 π r3

Curved surface area(CSA) = 2 π r2

Total surface area = TSA = 3 π r2

Prism :

Volume = Base area x h

Lateral Surface area = perimeter of the base x h

Pyramid:

Volume of a right pyramid = (1/3) × area of the base × height.

Area of the lateral faces of a right pyramid = (1/2) × perimeter of the base x slant height.

Area of whole surface of a right pyramid = area of the lateral faces + area of the base.

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